Dutch qualifier Lamens wins Osaka Open for first WTA title, breaks world’s top 100
Suzan Lamens won the tournament on Sunday night against Kimberly Birrell
Suzan Lamens
(Aflo/Panoramic)
Dutch qualifier Suzan Lamens beat Australian qualifier Kimberly Birrell 6-0, 6-4 to win the Osaka Open title at the Utsubo Tennis Center on Sunday night.
It’s the first WTA title for the 25-year-old and she will break into the world’s top 100 for the first time on Monday, predicted to be ranked No 87.
Lamens, ranked No 125, defeated Bulgarian Viktoriya Tomova, the No 6 seed (6-1, 6-2), Italian Lucia Bronzetti (6-3, 6-4), Romanian qualifier Ana Bogdan (4-6, 6-3, 6-3) and Frenchwoman Diane Parry, the No 7 seed (6-2, 6-4) ahead of her victory.
In the previous rounds of the Osaka tournament, Birrell, ranked No 150, beat Chinese Saisai Zheng (6-2, 6-3), Belgian Elise Mertens, the No 3 seed (3-6, 7-5, 4-1 ret.), Japanese wildcard Sara Saito (7-5, 6-4) and Japanese qualifier Aoi Ito (6-4, 6-3).
People in this post
More tennis news
Hurkacz ends eight-match losing run against Djokovic to storm into Shanghai third round
October 9, 2019: The day Spanish tennis legend Andres Gimeno passed away
October 8, 1989: The day Jim Courier won his first title, beating Stefan Edberg in the final
October 7, 1999: The day John McEnroe started his Davis Cup captaincy by offending Zimbabwe, his team’s first opponents
Djokovic wins seventh Beijing title and 102nd career crown as injured de Minaur retires